Math, asked by amruta9567, 1 year ago

if 3+√8/3-√8+3-√8/2+√8= a+b√2 , find the value of ba and b​

Answers

Answered by ankit8947
1

by rationalizing we get

(3+√8)^2 + (3-√8)^2

= 9+8+6√8 + 9+8-6√8

= 34

so a=34 & b=0.

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