Math, asked by biswasamit495, 1 year ago

if (3/8)^-5×(16/21)^-5=(2/7)^x find the x^3

Answers

Answered by abhi178
67
(3/8)^-5 × ( 16/21)^-5 = (2/7)^x

[ use, x^m.y^n = (xy)^mn]

{3/8 × 16/21}^-5 = (2/7)^x

(2/7)^-5 = (2/7)^x

[ use, P^m = P^n then, m = n ]

-5 = x

hence, x³ = (-5)³ = -125

Answered by nikitasingh79
36
(3/8)^-5×(16/21)^-5=(2/7)^x
[ (a^m × b^m) =(ab)^m

(3/8× 16/21)^-5 = (2/7)^x

(2/7)^-5 = (2/7)^x
[a^m = a^n then m=n]

x= -5
x³= (-5)³
x= -125
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