If(3/8)^-5×(16/21)^-5=(2/7)^x,find the x^3.
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Step-by-step explanation:
(3/8)^-5 × ( 16/21)^-5 = (2/7)^x
[ use, x^m.y^n = (xy)^mn]
{3/8 × 16/21}^-5 = (2/7)^x
(2/7)^-5 = (2/7)^x
[ use, P^m = P^n then, m = n ]
-5 = x
hence, x³ = (-5)³ = -125
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