Math, asked by saniya7052028, 10 months ago

If(3/8)^-5×(16/21)^-5=(2/7)^x,find the x^3.​

Answers

Answered by godimmortal92
1

Step-by-step explanation:

(3/8)^-5 × ( 16/21)^-5 = (2/7)^x

[ use, x^m.y^n = (xy)^mn]

{3/8 × 16/21}^-5 = (2/7)^x

(2/7)^-5 = (2/7)^x

[ use, P^m = P^n then, m = n ]

-5 = x

hence, x³ = (-5)³ = -125

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