Question

if 3(a-1)y -6x =2 and 4y -8x+10 =0 0are parallel find value of a
​

Answer 1

Answer:

Slope is - a/b an only further solving us there

Answer 2

The value of a is 2 and a≠11/15.

Given:

• $3(a - 1)y - 6x = 2$ and
• $4y - 8x + 10 = 0$

To find:

• If both lines are parallel than find the value of a.

Solution:

Concept to be used:

The standard linear equations are given as $a_1x+b_1y+c_1=0$ and $a_2x+b_2y+c_2=0$

Then,If these lines are parallel, then coefficients of the equations must satisfy the condition given below:

$\bf \frac{a_1}{a_2}=\frac{b_1}{b_2}\neq \frac{c_1}{c_2}$

Step 1:

Write the coefficients of x and y.

$-6x+3(a-1)y-2=0...eq1$

$a_1=-6$

$b_1=3(a-1)$

and

$c_1=-2$

$-8x+4y+10=0...eq2$

$a_2=-8$

$b_2=4$

and

$c_2=10$

Step 2:

Put the values in condition.

$\frac{-6}{-8}=\frac{3(a-1)}{4}\neq \frac{-2}{10}$

or

Take first two fractions:

$\frac{3}{4}=\frac{3(a-1)}{4}$

or

$3=3(a-1)$

or

$1=(a-1)$

or

$\bf \red{a=2}$

Take last two fractions:

$\frac{3(a-1)}{4}\neq \frac{-1}{5}$

or

$15(a-1)\neq -4$

or

$(a-1)\neq \frac{-4}{15}$

or

$a\neq \frac{-4}{15}+1$

or

$a\neq \frac{-4+15}{15}$

or

$a\neq \frac{11}{15}$

Thus,

The value of a is 2 and a≠11/15.

Learn more:

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