Math, asked by nicyNT, 7 months ago

If 3 A=4B=56, find A:B:C

Answers

Answered by prishashah0916
1

Answer:

let3A=4B=6C be x

A=x/3

B=x/4

C=x/6

therefore A:B:C=x/3:x/4:x/6

=1/3:1/4:1/6

taking LCM =12

1/3*12:1/4*12:1/6*12

4:3:2 is the required answer

please mark it as the brainliest answer

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