If 3 A=4B=56, find A:B:C
Answers
Answered by
1
Answer:
let3A=4B=6C be x
A=x/3
B=x/4
C=x/6
therefore A:B:C=x/3:x/4:x/6
=1/3:1/4:1/6
taking LCM =12
1/3*12:1/4*12:1/6*12
4:3:2 is the required answer
please mark it as the brainliest answer
Similar questions