if 3√a-5/2√b=6 and a=3b then 9a+25/4b
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If a+b+c=3 and a(^2)+b(^2)+c(^2)=5 and a(^3)+b(^3)+c(^3)=7 what is a(^ 4)+b(^4)+c(^4)? ... we have (4) (a^4+b^4+c^4) = 25 - 2(a^2b^2+a^2c^2+b^2c^2) Now, to get a ... a^3+3ab^2+3ac^2+3a^2b+3a^2c+6abc+b^3+3bc^2+3b^2c+c^3 ... 3(3)(5) = 27 + 14 - 45 = -4 and so (9) abc = -4/6 = -2/3 Then, finally, ...
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