If 3,a,b,15 is an Ap ,then value of a +b is
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3,a,b,15 are in a.p
so, their common difference must be same.
so, a-3=b-a=15-b.
considering first and last terms!!
a-3=15-b.
sending 'b' to lhs and '3' to rhs!
therefore, a+b=15+3=18.
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3 is term1
a is term2
b is term3
15 is term4
In an Ap term2-term1=term3-term2=term4-term3=...................term n -term n-1
15-b=a-3
15+3=a+b
a+b=18
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