If 3,A ,B,192 are consecutive terms of a Gp,find the value of A and B
Answers
Answered by
4
Step-by-step explanation:
3 r^3 = 192 ... r^3 = 64
A = 3 r
B = 3 r^2
Answered by
2
Step-by-step explanation:
3, a, b, 192 are parts of a geometric progression:
a1= 3
a2= 3*r = a
a3= 3*r^2 = b
a4= 3*r^3 = 192
==> 3r^3 = 192
Divide by 3:
==> r^3 = 192 /3 = 64
==> r^3 = 64
Now take the cubic root for both sides:
==> r= 4
Now let us calculater a and b
a2= a = 3*r = 3*4 = 12
a3= b = 3*r^2 = 3*4^2 = 3*16 = 48
==> a= 12 and b = 48
3, 12, 48, 192 are terms in a G.P where r = 4
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