Question

if √3|A x B| = A.B. Then what is the angle between A and B?

Answer 1

Answer:

your question is wrong it must be

$\frac{1}{ \sqrt{3} } |a \times b| = a.b$

Explanation:

then it would go like

$\frac{1}{ \sqrt{3} } ab \sin( \alpha ) = ab \cos \alpha \\ \binom{ \sin( \alpha ) }{ \cos( \alpha ) } = \sqrt{3} \\ \tan(60) = \sqrt{3} \\ \alpha = 60$