Question

if 3&(-2) are the zeros of polynomial x^2 +(a+1) x +b, find the value of a and b.​

Answer 1

Answer:

a=0

b=-6

Step-by-step explanation:

sum of the zeros = -b/a

-(a+1)=1

a=0

product of the zeros = c/a

b=3*-2

b=-6