Question

If 3 and ( -2) are the zeroes of the polynomial

x^2 +(a+1) x -b , find the value of a and b .​

Answer 1

Answer:

x

2

+(a+1)x+b is the quadratic polynomial.

2 and −3 are the zeros of the quadratic polynomial.

Thus, 2+(−3)=

1

−(a+1)

=>

1

(a+1)

=1

=>a+1=1

=>a=0

Also, 2×(−3)=b

=>b=−6

Answer 2

Answer:

A=1 and b=6 because 3 and -2 are the zero of the polynomial