Question

if 3 and(-2) are the zeroes of the polynomial x²+(a+1) x-b ,find the value of a and b​

Answer 1

Given Equation

x² + (a+1)x - b = 0

3 and -2 are the zeroes of the Polynomial

To Find

Value  of a and b

compare with

px² + qx + r = 0

we get

p = 1 , q = (a + 1) and r = -b

Let

α = 3 and β = -2

We know that

Sum of the Zeroes  = -q/p

(α + β) = -(a+1)

(3 - 2) = -(a+1)

1 =-a -1

1 + 1 = -a

a = -2

Product of the zeroes = r/p

αβ = -b

3×(-2) = -b

-6 = -b

b = 6

Answer

a = -2 and b = 6

Answer 2

Answer:

a = -2

b= 6

Step-by-step explanation:

3+(-2) =-(a+1)

1 = -a-1

a = -2

3(-2) = -b

-6= -b

b= 6