Question

if -3 and -2 are the zeros of the polynomial x^4-x^3-16x^2+4x+48 then find the remaining other zeros​

Answer 1

Answer:

x^4-x^3-16x^2+4x+48 = (x+3)(x³-4x²-4x+16)

= (x+3)(x+2)(x²-6x+8)

= (x+3)(x+2)(x-4)(x-2)

other zeros of the equ.

x = 2,4