If 3 and 3 are the roots of x^2+ax+b and 8 and 2 are the roots of x^2+ax+b=0,then find the roots of x^2+ax+b=0 are
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Answer:8,2 are the roots of x
2
+ax+β=0
⇒a=−(8+2)=−10
3,3 are the roots of x
2
+αx+b=0
⇒b=(3)(3)=9
x
2
+ax+b=0
⇒x
2
−10x+9=0
⇒x
2
−9x−x+9=0
⇒x(x−9)−1(x−9)=0
⇒(x−9)(x−1)=0
∴x=9orx=1
Step-by-step explanation:
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