If 3 and -3 are the solution of equate ax2+ bx -4 = 0, find the value of a and b
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Answer:
roots= -3,3
sum of the roots= -b/a
product of the roots= c/a
c=-4
3(-3)=-4/a
a=-4/-9
a=4/9
sum of the roots= -b/a
-3+3=-b/4/9
0=-b/4/9
b=0
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hope this helps u
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