Question

if √3 and -√3 are the zeroes of a polynomial of p(x) then p(x) is​

Answer 1

Answer:

p(x)= x²-3

Step-by-step explanation:

Quadratic equation =x²-(α+β)x+αβ=0

Here α=√3  β=-√3

α+β=√3-√3=0

αβ=√3 (-√3)=-3

hence equation=x²-(α+β)x+αβ=0

                       p(x)=x²-(0)x+(-3)

                       p(x)= x²-3=0