Question

if 3 and -3 are two zeroes of polynomial p(x)=x4+x3-11x2-9x+18
then
find
polynomial
the remaining two zeros of polynomial ​

Answer 1

Answer:

let x=3

p(3)=3x4+3x3-11x2-9x3+18

12+9-22-27+18

39-49= -10(negative)

now ...let x= -3

p(-3)= -3x4+(-3x3)-11x2-9x(-3)+18

-12-9-22+27+18

-43+45=2(positive)

so...2ans.

Answer 2

Step-by-step explanation:

Let p(x)= x^4 +x^3 -11x^2 -9x+18

A/q , its zeros are 3 and -3

→(x-3)(x+3) is a factor of p(x)

→Divide p(x) by x^2-9

We get , q(x) = x^2 +x -2

r(x)=0

For other zeros of p(x),

q(x)= 0

→x^2+ 2x-x-2=0

→x(x+2)-1(x+2)=0

→x= 1 or , -2

Other zeros are 1 and -2

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