Question

If 3 and 6 resistors are connected to a 6 V battery in parallel Ω Ω a) Calculate the effective resistance (1) b) What is the total current flowing through the circuit?​

Answer 1

Answer:

a) if resistors are connected in parallel combination, then 1/R (net) = (1/R1) + (1/R2)

1/R(net)= (1/3) + (1/6)

1/R(net)= (3/6) = (1/2)

R(net) = 2 ohm

b) According to Ohm's law, V = iR

6=i×2

i= 3A

Explanation:

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