If 3 balls are randomly drawn from a bowl containing 6 white and 5 black balls, what is the probability that one of the balls is white and the other two are black?
Answers
Answered by
2
Answer:
White = 6
Black = 5
Total = 6 + 5 = 11
3 out of 11 can be selected in ¹¹C₃ = 165 ways
one of the balls is white and the other two are black
one white ball out of 6 can be selected in ⁶C₁ = 6 ways
2 black balls out of 5 can be selected in ⁵C₂= 10 ways
Total ways of drawing one white and 2 black = 6 * 10 = 60
probability that one of the balls is white and the other two are black = 60/165
= 12/33
= 4/11
4/11 is the probability that one of the balls is white and the other two are black
Step-by-step explanation:
Similar questions