Question

If 3 chairs and 1 table costs Rs. 1500 and 6 chairs and 1 table costs Rs.2400. Form

linear equations to represent this situation.​

Answer 1

Answer:

let's the chair cost price be x and table be y

from 1st condition,

3x + y = 1500 -----(1)

6x + y = 2400 -----(2)

subtract the equations 1st and 2nd

6x + y = 2400

- 3x - y = -1500

___________

3x = 900

x = 300 -----(3)

put the value in equations 1st

6 × 300 + y = 2400

1800 + y = 2400

y = 2400 - 1800

y = 600

therefore, cost price of a chair is rs 300 and table is rs.600.

Answer 2

Answer:

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Step-by-step explanation:

Let the cost of 1 chair be Rs x and the cost of 1 table be Rs y.

So, 3x + y = 1500…(1)

And 6x + y = 2400…(2)

Equations (1) and (2) represent the situation described in the question.

From (1) and (2)

3x = 900

So, x = 300

So, y = 600

So, the cost of 1 chair is Rs 300

And the cost of 1 table is Rs 600