If 3 chairs and 1 table costs rs. 1500 and 6 chairs and 1 table costs rs.2400. form linear equation to represent this situation.
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The linear equation representing this situation is :- 3x + y = 1500
6x + y = 2400
Given :- cost of 3 chair and 1 table = 1500 ---- 1
cost of 6 chair and 1 table = 2400 ----- 2
To find :- Linear equation
Solution :-
- Let x be cost of 1 chair.
- Let y be cost of 1 table.
- If cost of 1 chair is x and cost of 1 table is y ,then from condition 1 ,
3x + y = 1500
- similarly from condition 2 ,
6x + y = 2400
- on solving these two equation , x= 300 ; y= 600
Cost of 1 chair = 300 ; Cost of 1 table = 600
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