Question

If 3 chairs and 1 table costs Rs. 1500 and 6 chairs and 1 table costs Rs.2400. Form
linear equations to represent this situation.​

Answer 1

Answer:

Linear equation for situation I : 3x + y = 1500

Linear equation for situation II : 6x + y = 2400

Step-by-step explanation:

Linear Equations to represent the two situations

Let, cost of each chair be ₹ x and cost of each table be ₹ y.

Case I : Cost of 3 chairs and 1 table is ₹ 1500

      3 chairs + 1 table = ₹ 1500

==> 3x + y = 1500  —————— (i)

Case II : Cost of 6 chairs and 1 table is ₹ 2400

      6 chairs + 1 table = ₹ 2400

==> 6x + y = 2400   —————— (ii)

If cost of each chair and table is required

Equation (ii) - equation (i) gives

      3x = 900

==> x= 300

Now, after substituting x = 300 in Equation (i) we get

      3( 300 ) + y = 1500

==> y = 1500 - 900

==> y = 600

∴ x = 300 and y = 600

Therefore, cost of each chair = x = ₹ 300 and cost of each table = y = ₹ 600