If 3 chairs and 2 tubes cost rs. 1200 and 5 chairs and 3 tubes cost rs. 1900, then the cost of 2 chairs and 2 tubes (in rs.) is
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Let the cost of 1 chairs be x
and cost of 1 tubes be y
3 chairs and 2 tubes costs Rs 1200
3x + 2y = 1200 .....(1). ×3
5 chairs and 3 tubes costs Rs 1900
5x + 3y = 1900 ........(2). ×2
From (1) & (2)
9x + 6y = 3600
(-)10x + 6y = 3800
-------------------------
-x = -200
Therefore , x = Rs 200
3x + 2y = 1200
600 + 2y = 100
therefore , y =Rs 300
We need to find ,
2x + 2y = ?
2 × 200 + 2 × 300 = 400 + 600 =Rs 1000
Cost of 2 chairs and 2 tubes is Rs 1000
Hope it helps
Let the cost of 1 chairs be x
and cost of 1 tubes be y
3 chairs and 2 tubes costs Rs 1200
3x + 2y = 1200 .....(1). ×3
5 chairs and 3 tubes costs Rs 1900
5x + 3y = 1900 ........(2). ×2
From (1) & (2)
9x + 6y = 3600
(-)10x + 6y = 3800
-------------------------
-x = -200
Therefore , x = Rs 200
3x + 2y = 1200
600 + 2y = 100
therefore , y =Rs 300
We need to find ,
2x + 2y = ?
2 × 200 + 2 × 300 = 400 + 600 =Rs 1000
Cost of 2 chairs and 2 tubes is Rs 1000
Hope it helps
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