Question

if 3 charges are placed at corners of equilateral triangle and force between any two charges is F then the force on each charge will be?

Answer 1

Answer:

Dear Student,

Please find below the solution to the asked query:

Given that the magnitude of each charge is +2C, and the force between each set of charges is F. Then,

F=14πε04l2F=14πε04l2

So, here all are the positive charges, then the forces due to two charges on the third acts away from respective charges. So, the angle between the two forces is 600. Then, according to the principle of superposition,

Fnet=F2+F2+2×F×F×cos (π3/)−−−−−−−−−−−−−−−−−−−−−−−−−−−√⇒Fnet=F2+F2+F2−−−−−−−−−−−−√⇒Fnet=3–√FFnet=F2+F2+2×F×F×cos π3⇒Fnet=F2+F2+F2⇒Fnet=3F

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Explanation: