Question

If 3 cos 0 = 2 then (2 sec?0 + 2 tan? 0 - 7) = ? ​

Answer 1

Step-by-step explanation:

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Answer 2

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cos θ = 2/3 = b/h = k 2sec2 θ + 2 tan2θ – 7 b = 2k,

h = 3k In ∆ABC, h2 = p2 + b2

⇒ (3k)2 = p2 + (2k)2

⇒ 9k2 = p2 + 4k2

⇒ p 2 = 9k2 – 4k2

⇒ p 2 = 5k2

⇒ p = √5k Then, Sec θ = h/b = 3k/2k = 3/2 and Tan θ = p/b = √5k/2k = √5/2 ⇒ 2 sec2 θ + 2 tan2 θ – 7

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