if 3 cos^2 A + 7 sin^2 A = 4, then what is the value of cot A , given that A is the acute angle
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Answer:
√3
Step-by-step explanation:
3cos² A + 7sin² A = 4
Dividing by sin² A on both sides
3cos² A/sin² A + 7sin² A/sin² A = 4/sin² A
3cot² A + 7 = 4cosec² A
3cot² A + 7 = 4( 1 + cot² A)
3cot² A + 7 = 4 + 4cot² A
7 - 4 = 4cot² A - 3cot² A
3 = cot² A
Taking square root on both sides
√3 = cot A
Therefore the value of cot A is √3.
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