Question

if 3 cos A -4sin A =0 ,evaluate (sin A +2 cos A)÷(3 cos A - sin A )​

Answer 1

Answer:

11/9

Step-by-step explanation:

3cos A-4sin A =0

► cosA = 4sinA / 3

$\frac{sin A +2 cos A}{3 cos A - sin A}$

=$\frac{sin A +{8sinA}/{3}}{4sinA - sin A}$

$=\frac{{11sinA}}{3(3sinA)}$

=11/9

Answer 2

Step-by-step explanation:

3cos A-4sin A =0

► cosA = 4sinA / 3

\frac{sin A +2 cos A}{3 cos A - sin A}

3cosA−sinA

sinA+2cosA

=\frac{sin A +{8sinA}/{3}}{4sinA - sin A}

4sinA−sinA

sinA+8sinA/3

=\frac{{11sinA}}{3(3sinA)}=

3(3sinA)

11sinA

=11/9