If 3 cos theta = 1 , find the value of 6 sin square theta + 10 square theta upon 4 cos theta
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Answer:
3 cosθ = 1
or, cosθ = 1/3
or, b/h = 1/3
b=1, h=3
According to Pythogorean theorem,
h² = p² + b²
or, 3² = p² + 1²
p = √8 = 2√2
sinθ = p/h =
tanθ = p/b = 2√2
=
=
= 40
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