Question

if 3 cos theta = 2 then (2 sec^2 + 2tan^2 theta -7​

Answer 1

Step-by-step explanation:

$3 \cos( \alpha ) = 2 \\ \cos( \alpha ) = \frac{2}{3} \\ \\ 2 \sec^{2} ( \alpha ) + 2 \tan^{2} ( \alpha ) - 7 \\ = 2 \sec^{2} ( \alpha ) + 2 \sec^{2} ( \alpha ) - 2- 7 \\ 4 \sec^{2} ( \alpha ) - 9 \\4 \times \frac{9}{4} - 9 \\ = 0$

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