Question

If 3 cot 0 = 2 then prove that
(4 sin 0 – 3 cos 0/ 2 sin 0 + 6 cos 0) =1/3.​

Answer 1

Answer:

Given,

3cotθ=2

cotθ=

3

2

tanθ=

2

3

2sinθ+6cosθ

4sinθ−3cosθ

=

2sinθ+6cosθ

4sinθ−3cosθ

×

sinθ

sinθ

---------- ( Multiply and divide by sinθ )

=

sinθ

2sinθ+6cosθ

sinθ

4sinθ−3cosθ

=

2+6(

sinθ

cosθ

)

4−3(

sinθ

cosθ

)

=

2+6cotθ

4−3cotθ

=

2+6×

3

2

4−3×

3

2

=

2+4

4−2

=

6

2

=

3

1

Answer 2

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