Question

If 3 cot θ =2, find the value of =( 4 sinθ-3 cosθ )/(2 sinθ +6sinθ)

Answer 1

let tita be 'a'.

=>cot a=2/3
cos a/sin a=2/3
=>cos a=2
=>sin a=3

(4*3-3*2)/(2*3+6*3)=(12-6)/(6-18)
=6/-12
=(-1/2)