IF 3 cot A=2, then find the value of
4 sinA- 3 COSA/
2sinA + 3COSA
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Answer:
3 cot A=2
cotA =2/3
adjacent side/opposite side = 2/3
So adjacent side =2 and opposite side =3
By Pythagoras theorem,
Consider triangle abc
BC=2 , AB=3
so AB²+BC²=AC²
So 3²+2²=AC² ==- AC= √13
SinA= AB/AC =3/√13
CosA=BC/AC=2/√13
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