Question

if 3 cot A=2 then find the value of 4sin A- 3cos A by 2sin A+3cosA

Answer 1

Answer:

Step-by-step explanation:

3 cot A=2

cotA =2/3

adjacent side/opposite side = 2/3

So adjacent side =2 and opposite side =3

By Pythagoras theorem,

Consider triangle abc

BC=2 , AB=3

so AB²+BC²=AC²

So 3²+2²=AC² ==- AC= √13

SinA= AB/AC =3/√13

CosA=BC/AC=2/√13

Now solve :-