If 3 cot A = 4, check whether
1 - tanA
1 + tan? A
= cosA-sin-A or not.
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Answer:
3cotA = 4
=> cotA = 4/3
=> Perpendicular = 3 & base = 4
=> H =(4^2+3^2)^-1/2 = 5
Given
LHS
(1-tanA)(1+tanA)
= (1-tan^2A)
= (1-3/4)
=1/4
RHS
CosA - SinA
=4/5-3/5
= 1/5
=> LHS≠RHS
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