if 3 cot A =4 , find the value of cosec sq A+1/cosec sq A-1
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19
Cot A=4/3
CotA=4/3=base/height
Let base =4x and height be 3x
By Pythagoras theorem,
Hypotenuse =5x
Cosec²A+1=hypotenuse/height +1
Cosec²A+1=5x/3x +1 =(5x+3x)/3x
Cosec²A=8x/3x=8/3
Cosec²-1=(5x-3x) /3x
Cosec²A =2x/3x=2/3
(8/3)/(2/3)
(8*3)/(3*2)
=8/2
=4
4 is your answer
I hope this much will help you
CotA=4/3=base/height
Let base =4x and height be 3x
By Pythagoras theorem,
Hypotenuse =5x
Cosec²A+1=hypotenuse/height +1
Cosec²A+1=5x/3x +1 =(5x+3x)/3x
Cosec²A=8x/3x=8/3
Cosec²-1=(5x-3x) /3x
Cosec²A =2x/3x=2/3
(8/3)/(2/3)
(8*3)/(3*2)
=8/2
=4
4 is your answer
I hope this much will help you
Answered by
10
Hope this helps you !
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