Question

if
3 Cot A = 4 then
find tan A and SinA​

Answer 1

Answer:

then tan A = 3/4 and you will get sinA from this

Answer 2

Answer:

Given,

3cotA=4

sinA=ACBC

cosA=ACAB

tanA=ABBC

cotA=BCAB=3k4k

AB=4k

BC=3k

By pythagoras Theorem we get,

AC2=AB2+BC2

AC2=42+32

AC2=16+9

AC2=25

AC2=25

AC=5k

L.H.S

=1+tan2A1−tan2A

=1+(43)21−(43)