Question

if 3 cot A =4 , then find the value of sec A will be​

Answer 1

Answer:

Here, option B is the correct one...

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Answer 2

Answer:

$3 \cot( \alpha ) = 4 \\ \cot( \alpha) = \frac{4}{3} \\ \tan( \alpha ) = \frac{3}{4} \\ \sec^{2} ( \alpha) = 1 + \tan^{2} ( \alpha ) \\ \sec( \alpha ) = \sqrt{1 + {( \frac{3}{4} )}^{2} } \\ \sec( \alpha) = \sqrt{1 + \frac{9}{16} } \\ \sec( \alpha) = \sqrt{ \frac{25}{16} } \\ \sec( \alpha ) = \frac{5}{4}$

5/4 is the right answer.