Question

If 3 cot theta=4 find 5sin theta +3 cos theta/5 sin theta -3 cos theta

Answer 1

Hi ,

Here I'm using A instead of theta

CotA= 4/3-----( 1 )

Now ,

(5sinA + 3cosA )/(5sinA - 3cosA )

Divide numerator and denominator with sinA , we get


= ( 5 + 3cosA/sinA)/(5 - 3cosA/sinA)

= ( 5 + 3cotA) / ( 5 - 3cotA )

= ( 5 + 3 ×4/3 )/ [ 5 - 3× ( 4/3 ) ]

= ( 5 + 4 ) / ( 5 - 4 )

= 9/1

= 9

I hope this helps you.

:)

Answer 2

Given that:
3 cot theta=4

we have to find:-
5sin theta +3 cos theta/5 sin theta -3 cos theta =?

Solution,
Formula used:
sin x = 1/√(1+cot²x)
cos x= √(1-sin²x)

hence,
5sin theta +3 cos theta/5 sin theta -3 cos theta = 9 answer

hope..
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