If 3 cot theta=4 find 9(5sin theta -3 cos theta)/5 sin theta +3 cos theta
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see the pic I hope you help !!
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bubbles24:
are u sure this is correct
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cot theeta ,=cos/sin
3cot theeta=4
cot theeta,=4/3
4=cos
3=sin
9(5*3-3*4)/5*3+3*4=9(15-12)/15+12=9(3)/27=27/27=1
so the answer is 1
3cot theeta=4
cot theeta,=4/3
4=cos
3=sin
9(5*3-3*4)/5*3+3*4=9(15-12)/15+12=9(3)/27=27/27=1
so the answer is 1
Thanks
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