Question

if 3 cot theta = 4 find the value of 5 cos theta - 2 sin theta / 5 cos theta + 3 sin theta​

Answer 1

Answer :

$\cot \: theta \: = \frac{4}{3} \\ \\ \tan \: theta = \frac{3}{4} = \frac{perpendicular}{base}$

By pythagoras theroem;

AC^2 = AB ^2 + BC ^2

AC^2 = 9 + 16

AC = 5

Putting all the values in the following equation we get;

= 5 (4/5) - 2 (3/5)/5 (4/5) + 3 (3/5)

= 4-6/5/4+9/5

= 14/29