If 3 Cot theta = 4 then ( 5 sin theta + 3 cos theta ) / (5 sin theta - 3 cos theta ) = ?
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3 Cot ¢ = 4
Cot ¢ = 4/3.
Therefore,
( 5 Sin ¢ + 3 Cos ¢) / ( 5 Sin¢ - 3 Cos ¢ ) = ( 5 + 3 Cot ¢ / 5 - 3 Cot ¢ ) [ Dividing Num . and Denominator by Sin ¢ ]
=> ( 5 + 3 × 4/3 ) / ( 5 - 3 × 4/3 )
=> ( 5 + 4 ) / ( 5 - 4 )
=> 9/1
=> 9.
Cot ¢ = 4/3.
Therefore,
( 5 Sin ¢ + 3 Cos ¢) / ( 5 Sin¢ - 3 Cos ¢ ) = ( 5 + 3 Cot ¢ / 5 - 3 Cot ¢ ) [ Dividing Num . and Denominator by Sin ¢ ]
=> ( 5 + 3 × 4/3 ) / ( 5 - 3 × 4/3 )
=> ( 5 + 4 ) / ( 5 - 4 )
=> 9/1
=> 9.
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