If 3 cubes of side 'a' are joined end to end, the surface area of the new cuboid formed is:
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Answer:
The dimensions of the cuboid so formed are as under:
l= length=15cm,b= breadth=5cm, h= height =5cm
Surface area of the cuboid =2(15×5+5×5+15×5)cm
2
=2(75+25+75)cm
2
=350cm
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Step-by-step explanation:
after joining ,
length =a+a+a =3a
breadth = a
height = a
surface area of cuboid = 2(lb + bh + hl)
= 2(3a*a + a*a + a*3a)
=2(3a²+a²+3a²)
= 2(7a²)
=14a²
if a=5
TSA = 14*5*5
= 350cm²
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