If Ā = 3 i-4 jand B = 2 i+16then the magnitude
and direction of Ā+ B will be
13, tan1 (12/5)
5, tan-1 (12/5)
12, tan1 (5/12)
10, tan1 (5/12)
Answers
Explanation:
If →A=3ˆi-4ˆj and →B=2ˆi+16ˆ j then the magnitude and direction of →A +→B will be. check-circle ... 10,tan-1(5/ 12). 13,tan-1(12/5). 12,tan-1(5/12).
Explanation:
If a=4i-3j and b=6i+8j, then what is the magnitude and direction of a, b, a-b, and b-a?
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a = 4i - 3j
Magnitude of a = |a| = √[(4^2) + {(-3)^2}] = 5 units
Direction of a = arc tan {(-3) / 4} = (360° - 36.87°) = 323.13° with positive X-axis
b = 6i + 8j
Magnitude of b = |b| = √{(6^2) + (8^2)} = 10 units
Direction of b = arc tan (8 / 6) = 53.13° with positive X-axis
(a - b) = (4 - 6)i + (-3 - 8)j = -2i - 11j
Magnitude of (a - b) = |a - b| = √[{(-2)^2} + {(-11)^2}] = 11.18 units
Direction of (a - b) = arc tan {(-11) / (-2)} = 180° + 79.695° = 259.695° with positive X-axis
(b - a) = - (a - b) = 2i + 11j
Magnitude of (b - a) = |b - a| = 11.18 units
Direction of (b - a) = arc tan (11 / 2) = 79.695° with positive X-axis
If a=4i-4j-3k and b=6i+8j, then what will the magnitude and direction of a+b be?
What is (a+b)-(a-b)?
What is a+b / a-b?
What is the magnitude and direction of A vector and B vector if A vector is 4i^-3j^ and B vector is
6i^+8j^?
How do you find the magnitudes and direction of these vectors (a) a, b, a+b, b-a, and a-b, if two vectors, a= 4i-3j and b= 6i+3j?
Given,
a=4i-3j, b=6i+8j
Magnitude of a= √(4) ²+(-3) ² = 5 units
Direction of a is along the South East making an angle of tan^-1(3/4) with the positive x axis.
Magnitude of b is √6²+8²=10 units
Direction of b is along the North East making an angle of tan^-1(8/6) with the positive x axis.
a-b=-2i-11j
Magnitude of a-b is √2²+11²= 5√5 units.
Direction of a-b is along the South East making an angle of tan^-1(11/2) with the negative x axis.
b-a= 2i+11j
Magnitude of b-a is √2²+11²= 5√5 units. Direction of b-a is along the North East making an angle of tan^-1(11/2) with the positive x axis.
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Vector a = 4i-3j , vector b= 6i+8j.
Magnitude of vector a = √{(4)^2+(-3)^2} = 5 units.
Direction of vector a = tan^-1(-3/4) , from positive x-axis.
Magnitude of vector b = √{(6)^2+(8)^2} = 10 units.
Direction of vector b = tan^-1(8/6) = tan^-1(4/3) , from positive x - axis.
Vector (a-b) = (4i-3j)-(6i+8j) = -2i -11j.
Magnitude of vector (a-b) =√{(-2)^2+(-11)^2} = 5√5 units.
Direction of vector (a-b) = tan^-1(11/2) from negative x-axis.
Vector (b-a)= (6i+8j-(4i-3j) = 2i +11j.
Magnitude of vector (b-a) = √{(2)^2+(11)^2} = 5√5 units.
Direction of vector (b-a) = tan^-1(11/2)from positive x-axis. Answer.
a = 4i-3j , |a| = 5 and direction is inverse-tan(-3/4)=-36.8°
b = 6i+8j , |b| = 10 direction inverse-tan(8/6) = 53.1°
a-b = -2i-11j , |a-b| = 11.18 and direction is inverse-tan(-11/-2) = 259.7°
b-a = 2i+11j , |b-a| = 11.18 and direction is inverse-tan (2/11) = 79.7°
If A+B=A-B, then the magnitude of B is?
If vector B added to vector C is 3.0i+6.0j, the result is a vector in the positive direction of the y axis with a magnitude equal to that of C. What is the magnitude of vector B?
When will the magnitude of A+B vector = the magnitude of A-B vector?
What is (a+b) (a+b)?
If the magnitude of vectors A, B and C are 3, 4 and 5 units respectively and A+B=C, what is the angle between vector A and B?
Magnitudes of a & b are 5 and 10 respectively, and the magnitudes of (a-b) and (b-a) have the same value, which is (125)^(1/2).
The formula for finding the magnitude of a vector
a = Xi + Yj
|a| = (X^2 + Y^2)^(1/2)
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Magnitude=!a!=√4^2+(-3)^2=5
!b!=√6^2+8^2=10
Directions of a and b are 4i/5–3j/5and 6i/10+8j/10
!a-b!=-5, !b-a!=5
Directions of a -b and b-a are,-2i/-5-11j/5=2i/5–11j/5, 2i/5+11j/5
If a=4i-4j-3k and b=6i+8j, then what will the magnitude and direction of a+b be?
What is (a+b)-(a-b)?
What is a+b / a-b?
What is the magnitude and direction of A vector and B vector if A vector is 4i^-3j^ and B vector is 6i^+8j^?
How do you find the magnitudes and direction of these vectors (a) a, b, a+b, b-a, and a-b, if two vectors, a= 4i-3j and b= 6i+3j?
If A+B=A-B, then the magnitude of B is?
If vector B added to vector C is 3.0i+6.0j, the result is a vector in the positive direction of the y axis with a magnitude equal to that of C. What is the magnitude of vector B?
When will the magnitude of A+B vector = the magnitude of A-B vector?
What is (a+b) (a+b)?
If the magnitude of vectors A, B and C are 3, 4 and 5 units respectively and A+B=C, what is the angle between vector A and B?