if 3 in a first term,common difference is 2 then find sumof first five terms
Answers
Answered by
8
Answer:
35
Step-by-step explanation:
Given :
a = 3
d = 2
Sn denotes sum of n terms
Sn = n/2 [ 2 a + ( n - 1 ) d ]
So put n = 5
S = 5/2 [ 2 a + ( 5 - 1 ) d ]
= 5/2 [ 2 × 3 + 4 × 2 ]
= 5/2 [ 6 + 8 ]
= 5/2 × 14
= 5 × 7
= 35
ANSWER :
35
shreya504:
great answer
Answered by
3
hey here is your answer:-
Given.....,
a = 3
d=2
n=5
put the value in formula of sum
formula of SUm
Sn = n/2 ( 2a + (n-1)d)
= 5/2 ( 6 + 4*2)
= 5/2 * 14
= 35
Given.....,
a = 3
d=2
n=5
put the value in formula of sum
formula of SUm
Sn = n/2 ( 2a + (n-1)d)
= 5/2 ( 6 + 4*2)
= 5/2 * 14
= 35
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