if 3 is 0 of the polynomial p(x)=2x sq- 5x+7a find the value of a
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3
Substituting x=3 in the given equation,
➡2x²-5x+7a=0
➡2(3)²-5(3)+7a=0
➡18-15+7a=0
➡3+7a=0
➡7a= -3
➡a= -3/7
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Answered by
10
P(3)=(2×3)^2-5×2-7a=0
=6^2-10-7a=0
=36-10-7a=0
26-7a=0
=-7a=-26
=7a=26
=a=26/7
=3.71
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