if ×-3 is a factor of ׳+aײ+b×+18 and a+b =-7 find a and b
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Answer:
x-3=0
x=3
p(x)=x³-ax²+bx+18
p(3)=(3)³-a(3)²+b(3)+18
27-a(9)+3b+18=0
-9a+3b+45=0
3(-3a+b+15)=0
-3a+b+15=0/3
3a-b-15=0
3a-b=15———eq-1
a+b=-7———eq-2
From eq-1 & eq-2
3a-b=15
+ a+b=-7
—————
4a=8
a=8/4
→a=2
substitute a=2 in eq-1
3(2)-b=15
6-b=15
6-15=b
→b=-9
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