Question

if 3 is a one of the zeroes of p(x) = x2+kx+9 then the value of k =

Answer 1

Given.
3 is a zero of the given polynomial.

So f(3)=0
→3²+3k+9=0
→9+3k+9=0
→3k=-18
→k=(-18)/3=(-6)

So k=(-6) is your answer....

Hope it Helps...
Regards,
Leukonov.

Answer 2

P(x)=x^2+kx+9 X=3 Sub x value. (3)^2+k(3)+9=0 9+3k+9=0 3k+18=0 3k=-18 K=-18/3 =>K=-6