Math, asked by khushiacharjee547, 2 months ago

If 3 is a root of equation kx^square+7x+3=0then the value of k is
1)-4
2)1/4
3)4
4)1

Answers

Answered by dollypatel1353

0

Answer:

kx^2+7x+3=0

k(3)^2+7(3)+3=0

9k+21+3=0

9k= -24

k = -8/3

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