Question

if -3 is a root of quadratic equation kx²+2x-3=0 then find value of k​

Answer 1

Answer:

kx²+2x-3=0

put, x= -3;

k(-3)²+2(-3)-3=0

9k-6-3=0

9k-9=0

9k=9

•°•k=1

Step-by-step explanation:

Answer 2

Given:

Equation: kx²+2x-3=0

To find:

The value of k

Solution:

The required value of k is 1.

We can obtain the value by substituting the given root of the equation

The equation's root= -3

We know that on putting x= -3, the equation will be equal to 0.

The given equation: kx²+2x-3=0

On putting the value of x, we get

k($-3)^{2}$+2(-3)-3=0

9k-6-3=0

9k-9=0

9k=9

k=9/9

k=1

So, k's value is 1.

Therefore, the required value of k is 1.