Question

if 3 is a root of the equation 7x2-(k+1)x+3=0 then value of k is...​

Answer 1

sᴏʟᴜᴛɪᴏɴ :-

_______________________

=> ʀᴏᴏᴛ ᴏғ ᴇǫᴜᴀᴛɪᴏɴ => 3

=> ᴇǫᴜᴀᴛɪᴏɴ => 7x^2 - (k+1)x + 3

_______________________

0 = 7(3)^2 - (k+1)(3) + 3

0 = 63 - 3k - 3 + 3

-63 = -3k

k = -63/-3

_______________________

k = 21

Answer 2

Answer:

Step-by-step explanation:

p(x) = 7x^2 - (k+1)x + 3 = 0

p(3) = 7(9) - (k+1)3 + 3 = 0

          63 -3k - 3 + 3 = 0

          63 = 3k

          k = 21

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